(2x^3-16/3x^2+6x-24)(9x+18/5x^2+10x+20)

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Solution for (2x^3-16/3x^2+6x-24)(9x+18/5x^2+10x+20) equation:


x in (-oo:+oo)

(2*x^3-((16/3)*x^2)+6*x-24)*((18/5)*x^2+9*x+10*x+20) = 0

(2*x^3+(-16/3)*x^2+6*x-24)*((18/5)*x^2+9*x+10*x+20) = 0

(2*x^3-16/3*x^2+6*x-24)*(18/5*x^2+19*x+20) = 0

2*x^3-16/3*x^2+6*x-24 = 0

2*(x^3-8/3*x^2+3*x-12) = 0

x^3+(-8/3)*x^2+3*x-12 = 0

x^3+(-8/3)*x^2+3*x-12 = 0 // * 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 9, -9, 12, -12, 18, -18, 36, -36 }

1

x = 1

3*x^3-8*x^2+9*x-36 = -32

1

-1

x = -1

3*x^3-8*x^2+9*x-36 = -56

-1

2

x = 2

3*x^3-8*x^2+9*x-36 = -26

2

-2

x = -2

3*x^3-8*x^2+9*x-36 = -110

-2

3

x = 3

3*x^3-8*x^2+9*x-36 = 0

3

x-3

3*x^2+x+12

3*x^3-8*x^2+9*x-36

x-3

9*x^2-3*x^3

x^2+9*x-36

3*x-x^2

12*x-36

36-12*x

0

3*x^2+x+12 = 0

DELTA = 1^2-(3*4*12)

DELTA = -143

DELTA < 0

x in { 3}

2*(x-3) = 0

18/5*x^2+19*x+20 = 0

18/5*x^2+19*x+20 = 0

DELTA = 19^2-(18/5*4*20)

DELTA = 73

DELTA > 0

x = (73^(1/2)-19)/(2*18/5) or x = (-73^(1/2)-19)/(2*18/5)

x = 5/36*(73^(1/2)-19) or x = -5/36*(73^(1/2)+19)

(x+5/36*(73^(1/2)+19))*(x-5/36*(73^(1/2)-19)) = 0

2*(x-3)*(x+5/36*(73^(1/2)+19))*(x-5/36*(73^(1/2)-19)) = 0

( x+5/36*(73^(1/2)+19) )

x+5/36*(73^(1/2)+19) = 0 // - 5/36*(73^(1/2)+19)

x = -(5/36*(73^(1/2)+19))

x = -5/36*(73^(1/2)+19)

( x-3 )

x-3 = 0 // + 3

x = 3

( x-5/36*(73^(1/2)-19) )

x-5/36*(73^(1/2)-19) = 0 // + -5/36*(73^(1/2)-19)

x = -(-5/36*(73^(1/2)-19))

x = 5/36*(73^(1/2)-19)

x in { -5/36*(73^(1/2)+19), 3, 5/36*(73^(1/2)-19) }

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